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Solve a 1dimensional equation to find the roots. This does alternating secant and bisection steps. It will work for any function, discontinuous or not. For a nasty function, it might be a factor of 2 slower than bisection, but for a nearlylinear function, it can be much faster than bisection.
Functions  
float 







Variables  
__package__ = None hash(x) 
Function Details 
Find a root of an equation.

Find a zero in an array y. This function assumes there is known to be a root in [xl,xh]. It returns a realnumber index into the array which linearly interpolates to zero. 
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